If v is an eigenvector of the matrix AA^T (A multiplied by its transpose) with eigenvalue λ, show that A^Tv is an eigenvector of A^TA.
Please Help >_<
Last edited by CaptainBlack; Nov 15th 2010 at 06:46 AM.
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By hypothesis there exits an scalar such that . Then,
That is, is an eigenvector of .
What ideas have you had so far?
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