If v is an eigenvector of the matrix AA^T (A multiplied by its transpose) with eigenvalue λ, show that A^Tv is an eigenvector of A^TA. Please Help >_<
Last edited by CaptainBlack; November 15th 2010 at 06:46 AM.
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By hypothesis there exits an scalar such that . Then, That is, is an eigenvector of . Regards.
What ideas have you had so far?
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