Prove that if Q is an orthogonal matrix, the det(Q)=(+-)1.
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What ideas have you had so far?
Originally Posted by Ackbeet What ideas have you had so far? Actually I think I've got it. Using the two theorems (if allowed) of det(AB)=det(A)det(B) and detA=detA^t...without explict detail we will eventually end up (det(Q))^2=1 which will leave us with det(Q)= 1 or -1
Perfect. You don't need to add any more - I think you're done.
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