to prove
Η * Η’ = Η’ * Η
Η= [a b]
[c d]
H'=[a' b']
[c' d']
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to prove
Η * Η’ = Η’ * Η
Η= [a b]
[c d]
H'=[a' b']
[c' d']
Do the multiplication matrix and show us what you get! (Smile)
i Do the multiplication and i find a='a and d='d
but my teacher say a’ = a b’ = c c’ = b and d’ = d
And
Well, I'm not sure what you are trying to do, but your original post says prove that H.H' = H'.H
Since we know that a = a', d = d', c = b' and b = c', then H.H' = H'.H is proved.
we dont know that a = a', d = d', c = b' and b = c',
we are trying to find that h*h'=h'*h
and i think that the anser is a = a', d = d', c = b' and b = c',
but i am not completely sure
Well, for H.H' to be equal to H'.H, we must have a = a', d = d', c = b' and b = c'
thnks dude!
may the force be with you!!
Uh...okay... (Itwasntme)
Thanks!
sorry can you explain the answer plzzzzz??
You cannot prove that
H.H' = H'H
unless we know that a = a', d = d', c = b' and b = c'
All you appear to have here is two unrelated matrices, H and H'.
You cannot then prove that "H*H'= H'*H" because it is not true: matrix multiplication is not commutative.
Or did you mean that H' is the transpose of H? No, that doesn't work either. So I don't know what you are asking.