A = ( -1 1 -1)
( 0 c 0)
(3+2c-c^2 b 3)
can only be diagonalised for some values of the parameters b and c . Construct a table
showing the values of b and c for which diagonalisation is possible. You must show
For this I have done the following:
P(ƛ) = -(c -ƛ)((-1-ƛ)(3-ƛ)+3+2c-c^2)
For what I finally got
c-ƛ =0 -> ƛ =c
Then ƛ^2 -2ƛ +2C -ƛ^2=0
and then getting the value for ƛ
ƛ = 1+-(1-c)
Is this right?
And what should I do next with this problem?
Thank you for your time.