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Math Help - Basis for the Nullspace of A

  1. #1
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    Basis for the Nullspace of A

    I have no idea what I'm doing wrong. Ideas?

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  2. #2
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    Your answer is absolutely correct, it's the grading scheme that is wrong. Perhaps it was programmed to accept only (3,5,1,0,0) as the first basis vector, rather than (3,5,1,0,0)?
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  3. #3
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    Quote Originally Posted by ChrisEffinSmith View Post
    I have no idea what I'm doing wrong. Ideas?

    Interchange a couple of rows, and finish up the elimination.
    Can take the third and fifth unknowns free.
    I believe you must have already done this.

    So if you're saying {v_1, v_2} is your basis for Null(A), then I don't see what's wrong.


    EDIT: I wasn't aware of the preceding post until after I made mine.
    Anyway, the two vectors you obtained are exactly the two that I obtained by simply doing what I suggested above.
    Last edited by PiperAlpha167; October 24th 2010 at 07:30 PM.
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