# Math Help - Basis for the Nullspace of A

1. ## Basis for the Nullspace of A

I have no idea what I'm doing wrong. Ideas?

2. Your answer is absolutely correct, it's the grading scheme that is wrong. Perhaps it was programmed to accept only (3,5,–1,0,0) as the first basis vector, rather than (–3,–5,1,0,0)?

3. Originally Posted by ChrisEffinSmith
I have no idea what I'm doing wrong. Ideas?

Interchange a couple of rows, and finish up the elimination.
Can take the third and fifth unknowns free.
I believe you must have already done this.

So if you're saying {v_1, v_2} is your basis for Null(A), then I don't see what's wrong.

EDIT: I wasn't aware of the preceding post until after I made mine.
Anyway, the two vectors you obtained are exactly the two that I obtained by simply doing what I suggested above.