I have no idea what I'm doing wrong. Ideas?

http://usera.imagecave.com/hotrod73d...whatswrong.JPG

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- October 23rd 2010, 09:38 AMChrisEffinSmithBasis for the Nullspace of A
I have no idea what I'm doing wrong. Ideas?

http://usera.imagecave.com/hotrod73d...whatswrong.JPG - October 24th 2010, 12:52 AMOpalg
Your answer is absolutely correct, it's the grading scheme that is wrong. Perhaps it was programmed to accept only (3,5,–1,0,0) as the first basis vector, rather than (–3,–5,1,0,0)?

- October 24th 2010, 01:03 AMPiperAlpha167
Interchange a couple of rows, and finish up the elimination.

Can take the third and fifth unknowns free.

I believe you must have already done this.

So if you're saying {v_1, v_2} is your basis for Null(A), then I don't see what's wrong.

EDIT: I wasn't aware of the preceding post until after I made mine.

Anyway, the two vectors you obtained are exactly the two that I obtained by simply doing what I suggested above.