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Thread: prove inverse transformation is linear

  1. #1
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    prove inverse transformation is linear

    Could someone help me with the following problem?

    Suppose A is a linear transformation from the x-y plane to itself. Show that A^-1 is also a linear transformation (if it exists).

    Thanks for the help!
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  2. #2
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    Quote Originally Posted by sdh2106 View Post
    Could someone help me with the following problem?

    Suppose A is a linear transformation from the x-y plane to itself. Show that A^-1 is also a linear transformation (if it exists).

    Thanks for the help!

    Suppose $\displaystyle A:R^2\to R^2$ linear transformation which is Bijection. Let us show now that $\displaystyle A^{-1}:R^2\to R^2$ is also linear transformation.

    Suppose $\displaystyle a,b \in R^2$, $\displaystyle A$ is a bijection, there are exist unique vectors $\displaystyle c,d \in R^2$ which for them:

    $\displaystyle A(c)=a$ and $\displaystyle A(d)=b$.

    From the linearity of $\displaystyle A$ we have also:

    $\displaystyle A(c+d)=A(c)+A(d)=a+b$ and $\displaystyle A(kc)=kA(c)=ka$.

    Now, by definition of inverse transformation, $\displaystyle A^{-1}(a)=c$ , $\displaystyle A^{-1}(b)=d$ , $\displaystyle A^{-1}(a+b)=c+d$ and $\displaystyle A^{-1}(ka)=kc$.

    Hence:

    $\displaystyle A^{-1}(a+b)=c+d=A^{-1}(a)+A^{-1}(b)$ and $\displaystyle A^{-1}(ka)=kc=A^{-1}(a)$, therefor $\displaystyle A$ is linear transformation.
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  3. #3
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    great explanation. thanks again!
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