Could someone help me with the following problem?

Suppose A is a linear transformation from the x-y plane to itself. Show that A^-1 is also a linear transformation (if it exists).

Thanks for the help!

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- Oct 12th 2010, 04:24 PMsdh2106prove inverse transformation is linear
Could someone help me with the following problem?

Suppose A is a linear transformation from the x-y plane to itself. Show that A^-1 is also a linear transformation (if it exists).

Thanks for the help! - Oct 12th 2010, 04:55 PMAlso sprach Zarathustra

Suppose $\displaystyle A:R^2\to R^2$ linear transformation which is. Let us show now that $\displaystyle A^{-1}:R^2\to R^2$ is also linear transformation.__Bijection__

Suppose $\displaystyle a,b \in R^2$, $\displaystyle A$ is a bijection, there are exist unique vectors $\displaystyle c,d \in R^2$ which for them:

$\displaystyle A(c)=a$ and $\displaystyle A(d)=b$.

From the linearity of $\displaystyle A$ we have also:

$\displaystyle A(c+d)=A(c)+A(d)=a+b$ and $\displaystyle A(kc)=kA(c)=ka$.

Now, by definition of inverse transformation, $\displaystyle A^{-1}(a)=c$ , $\displaystyle A^{-1}(b)=d$ , $\displaystyle A^{-1}(a+b)=c+d$ and $\displaystyle A^{-1}(ka)=kc$.

Hence:

$\displaystyle A^{-1}(a+b)=c+d=A^{-1}(a)+A^{-1}(b)$ and $\displaystyle A^{-1}(ka)=kc=A^{-1}(a)$, therefor $\displaystyle A$ is linear transformation. - Oct 14th 2010, 05:20 AMsdh2106
great explanation. thanks again!