Originally Posted by ThePerfectHacker You can always use the quadtric formula!!! Yes, but that's rather 'nasty' as well, I don't like it
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Thanks TD! for help, finally solved!
Originally Posted by DenMac21 Thanks TD! for help, finally solved! You're welcome
Originally Posted by TD! I haven't really looked into the problem so I haven't been able to come up with a more elegant solution, but here's a go.
We have a 4th degree polynomial without a 3rd degree term so a possible factorization would be two second degree polynomials with opposite lineair terms.
Identifying coefficients gives us a 3x3 system
So we have the following factorization
Then it's just solving two quadratics, solutions are
Of course, these solutions for x depend on a, so I don't see why a negative solution would be impossible - for certain values of the parameter a. Very well done.
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