Element of a Group

Let $G$ be a finite group. Prove that if $\mid G \mid$ is odd then every element in $g \in G$ can be expressed as $g=x^2$ for some $x \in G$.
Let $G$ be a finite group. Prove that if $\mid G \mid$ is odd then every element in $g \in G$ can be expressed as $g=x^2$ for some $x \in G$.
Use the pigeon-hole principle. This can be used as $x^2 \neq 1$ for $x \neq 1$, because the order of an element must divide the order of the group, so no element can have order 2.