Originally Posted by
gthoren I have bee asked to show that for the eigenvalue problem:
eta e= lamda(eta) e
Show that:
lamda(eta) = ( lamda(b) -1 )/(2lamda(b))
where eta = Eularian strain tensor = 1/2(I-inv(B))
lamda(eta) = eigenvalues of eta
e = eigenvector of eta
B = left cauchy-Green tensor
lamda(b) = eigenvalues of B
I don't really know where to start. I've come up with this so far:
inv(B)e = (1-2lamda(eta))e
Any tips what to do?
Thanks!