Last edited by gthoren; Oct 5th 2010 at 05:44 AM.
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Originally Posted by gthoren I have bee asked to show that for the eigenvalue problem:
eta e= lamda(eta) e
Show that: lamda(eta) = ( lamda(b) -1 )/(2lamda(b))
where eta = Eularian strain tensor = 1/2(I-inv(B))
lamda(eta) = eigenvalues of eta e = eigenvector of eta
B = left cauchy-Green tensor
lamda(b) = eigenvalues of B
I don't really know where to start. I've come up with this so far:
inv(B)e = (1-2lamda(eta))e
Any tips what to do?
I think it's pretty hard to understand your symbols: either you write in LaTeX, or else call E instead "eta", w instead lambda or the like.
Last edited by gthoren; Oct 5th 2010 at 04:45 AM.