how to prove this:

LetGbe a group andaeGan element of finite order. Then|<a>| = |a|.

Thank you!! ;]

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- Sep 27th 2010, 11:08 PM #1

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- Sep 27th 2010, 11:15 PM #2

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- Sep 27th 2010, 11:20 PM #3

- Sep 27th 2010, 11:21 PM #4

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- Sep 27th 2010, 11:37 PM #5

- Sep 27th 2010, 11:43 PM #6

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A proof on the corollary of the Lagrange's Theorem. It's |a| divides |G|. I just stated there that a part of the proof for the corollary is to note/recall that |<a>| = |a|. And i think i also have to show the proof for |<a>| = |a|, because maybe my classmates might ask. ;]

- Sep 28th 2010, 12:01 AM #7

- Sep 28th 2010, 12:13 AM #8

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- Sep 28th 2010, 12:35 AM #9