how to prove this:

LetGbe a group andaeGan element of finite order. Then|<a>| = |a|.

Thank you!! ;]

Results 1 to 9 of 9

- Sep 27th 2010, 11:08 PM #1

- Joined
- Aug 2010
- From
- Sibulan
- Posts
- 12

- Sep 27th 2010, 11:15 PM #2

- Joined
- Apr 2005
- Posts
- 19,781
- Thanks
- 3030

- Sep 27th 2010, 11:20 PM #3

- Sep 27th 2010, 11:21 PM #4

- Joined
- Aug 2010
- From
- Sibulan
- Posts
- 12

- Sep 27th 2010, 11:37 PM #5

- Sep 27th 2010, 11:43 PM #6

- Joined
- Aug 2010
- From
- Sibulan
- Posts
- 12

A proof on the corollary of the Lagrange's Theorem. It's |a| divides |G|. I just stated there that a part of the proof for the corollary is to note/recall that |<a>| = |a|. And i think i also have to show the proof for |<a>| = |a|, because maybe my classmates might ask. ;]

- Sep 28th 2010, 12:01 AM #7

- Sep 28th 2010, 12:13 AM #8

- Joined
- Aug 2010
- From
- Sibulan
- Posts
- 12

- Sep 28th 2010, 12:35 AM #9