Let A be an n x n (square) matrix and let x and y be vectors in all real numbers. Show that if Ax=Ay and x does not equal y, then the matrix A must be singular.

How do I start on this problem?

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- September 15th 2010, 06:22 PMguyonfire89Singular Matrices Theorem
Let A be an n x n (square) matrix and let x and y be vectors in all real numbers. Show that if Ax=Ay and x does not equal y, then the matrix A must be singular.

How do I start on this problem? - September 15th 2010, 06:23 PMAckbeet
What have you tried so far? I would probably do a proof by contradiction.

- September 15th 2010, 06:32 PMguyonfire89
That's the problem, I never learned how to prove a matrix is nonsingular or singular. I know what they mean, that they have an inverse or don't.

Are you saying that I should try to show that it has an inverse? Or can I just do this by trying to find a determinate which is zero? - September 16th 2010, 02:53 AMAckbeet
I'm asking what you could do if the matrix had an inverse. Take a look at your equation there.