Proof:

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- Sep 9th 2010, 08:24 AMmath2009Proof: rank(AB)+n >= rank(A)+rank(B)

Proof:

- Sep 9th 2010, 01:55 PMNonCommAlg
this is a nice problem! i think by that you mean the field of real numbers well, you really don't need your ground field to be so i'll assume that is any field and and are

and matrices respectively, with entries in let be the linear transformations corresponding to and respectively, i.e. and

are defined by for all and for all

**claim.**where means "dimension of the kernel".

**proof**. define by for all note that is well-defined because if , then and thus

it's obvious that is linear and therefore, by the rank-nulity theorem, we have

but and

now solving your problem is easy: applying the above claim and the rank-nulity theorem we have:

- Sep 9th 2010, 04:03 PMmath2009
I make a mistake

It should be

- Sep 9th 2010, 04:56 PMNonCommAlg
- Sep 9th 2010, 06:28 PMmath2009
The key is constructing a transformation.

It's different with normal