http://i33.tinypic.com/28qsntd.jpg

Will put up what i have done in a couple of mins

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- August 26th 2010, 06:48 AMadam_leedsSystem of linear equations - types of solutions.
http://i33.tinypic.com/28qsntd.jpg

Will put up what i have done in a couple of mins - August 26th 2010, 06:58 AMadam_leeds
- August 26th 2010, 08:09 AMadam_leeds
Have i done the echelon system reduction correct?

- August 26th 2010, 09:00 AMAckbeet
I follow you up until this point (it's your third line):

What row operation did you do next? - August 26th 2010, 09:39 AMadam_leeds
- August 26th 2010, 09:49 AMAckbeet
Hmm. Two comments:

1. Your fourth line doesn't look like that at all.

2. I don't think that's the right ERO for this stage in the game. I would do 3rd - (2nd x ( -3)).

Come to think of it,*that's*what your fourth line looks like. I got your numeral 1's mixed up with your parentheses (maybe you should make your parentheses more curved, so they don't get confused with 1's). You actually did what I suggested in my second comment.

[EDIT]: I think you edited your post. Pick up my comments from here on down.

So I now follow you down to the fifth line. Your row reduction is correct, I believe.

Your logic is incorrect in your answer to i. In order for that entry in the matrix to be nonzero, you must have**both****and**(not**or**, as you wrote).

I would agree that for ii, it's impossible. And I agree with your answer for iii.

Does that help? - August 26th 2010, 09:52 AMadam_leeds
- August 26th 2010, 09:56 AMAckbeet
Hmm. Well, that is a bit puzzling. However, I think your row reduction is correct. Perhaps you could say the empty set?

- August 28th 2010, 05:45 AMadam_leeds
Im still a bit worried that what ive done is wrong as iv asks for ii. But i've got it not to work. Can anyone else check please?

- August 28th 2010, 10:47 AMPlato