where S = {[ 2a-b, a , b , -a ] | a,b are real numbers}

how do prove and show this one?

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- Aug 25th 2010, 11:42 AMexperiment00Is S = real space(R^3)
where S = {[ 2a-b, a , b , -a ] | a,b are real numbers}

how do prove and show this one? - Aug 25th 2010, 12:53 PMHaven
Can you explain what you mean by real space($\displaystyle \mathbb{R}^3$). I can't find that terminology in any of my algebra texts.

Are you asking if S forms a basis for $\displaystyle \mathbb{R}^3$? - Aug 25th 2010, 07:04 PMtonio
- Aug 26th 2010, 02:28 AMAckbeetQuote:

The vector $\displaystyle (2a-b,a,b,-a)$ is 4-dimensional and thus cannot belong to $\displaystyle \mathbb{R}^{3}.$