hmm, how do i prove this one? plus, (M^t)^-1 = (M^-1)^t
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Originally Posted by experiment00 hmm, how do i prove this one? plus, (M^t)^-1 = (M^-1)^t from $\displaystyle A^T(A^{-1})^T=(A^{-1}A)^T=I^T = I$ we conclude that it's really $\displaystyle (A^{-1})^T=(A^T)^{-1}$
if M is invertible, then $\displaystyle \det(M)\neq 0$ $\displaystyle \because~\det(M^T)=\det(M)\neq 0$, so $\displaystyle M^T$ is invertible
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