Can i just find the triple scalar product a.(b x c) And if it = 0 then it lies in the plane?
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Originally Posted by adam_leeds Can i just find the triple scalar product a.(b x c) = 0 then it lies in the plane? Yes this is true for three non-zero vectors.
Originally Posted by Plato Yes this is true for three non-zero vectors. Thanks So for v1 = (−2, 2, 0), v2 = (6, 1, 4) and v3 = (2, 0,−4) The cross product is 58
I don't understand what you are doing.
Originally Posted by Plato I don't understand what you are doing. Yeah i did something wrong, i used this to help me thanks
A short cut for the triple product is this: If , , and [tex]v_3= <x_3, y_3, z_3> then the cross product is the determinant:
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