Three vectors lie in a plane

Can i just find the triple scalar product a.(b x c)

And if it = 0 then it lies in the plane?

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Originally Posted by adam_leeds

Can i just find the triple scalar product a.(b x c) = 0 then it lies in the plane?

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Yes this is true for three non-zero vectors.

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Originally Posted by Plato

Yes this is true for three non-zero vectors.

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Thanks

So for v1 = (−2, 2, 0), v2 = (6, 1, 4) and v3 = (2, 0,−4)

The cross product is 58

I don't understand what you are doing.

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Originally Posted by Plato

I don't understand what you are doing.

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Yeah i did something wrong, i used this to help me YouTube - The Cross Product :) thanks

A short cut for the triple product is this:
If , , and [tex]v_3= <x_3, y_3, z_3> then the cross product is the determinant: