Hey, thanks thats answered half my questions but unfortunatly isn't right. ( is a past exam paper have the answer but didn't know how to get there

)

The unit vector part is the part i was missing thanks.

So

A = [ 2 -1, -1 1 ] Eigenvectors = [ -0.53, -0.85 ], [ -0.85,0.53 ]

Eigenvalues = 0.38, 2.62

So solving as simulataneous equations ( for L = 0.38 )

(1) ( 2 - Lamda )x(1) + (-1)x(2) = 0 => 1.62x(1) - x(2) = 0

(2) (-1)x(1) + (1-Lamda)x(1) = 0 => -x(1) + 0.62x(2) = 0

now obviously from this we get the answer in the above post

1.62x(1) = x(2)

and 0.62x(2) = x(1)

So getting the unit vector = [0.53, 0.85], any idea why the signs would be different to the 'answer', I personally can't see why unless for some reason you take 1.62x(1) from a side in (1) so

(1) -x(2) = -1.62x(1)

but i'm not sure why on earth you would do this? Again thanks for any help given.