The line r=a+tb and the plane r.n=p. b.n is not equal to zero. Prove that the position vector of the point of intersection of the line and plane is $\displaystyle a+\frac{(p-a.n)b}{b.n}$
I have no idea how to start this.
Thanks
The line r=a+tb and the plane r.n=p. b.n is not equal to zero. Prove that the position vector of the point of intersection of the line and plane is $\displaystyle a+\frac{(p-a.n)b}{b.n}$
I have no idea how to start this.
Thanks