Finding parametric scalar equations of lines which are parallel to a plane

The question: Let pi be the plane 2x-3y-6z=6 and M be the point of intersection of the plane with the y axis. Find parametric scalar equations of the line m which lies on the plane pi, passes through the point M and m is parallel to the xz plane.

My attempt:

M must be (o,-2,0)

And i know the eqn of a parametric vector eqn of a line is r=r0+tv

Where c will not have a y component. Am i right in then solving the line x+Z-2=0

with 2x-3y-6z to find the vector? Then the line will be r=-2j=t(v)