Hint: Any two Sylow-p subgroups of G are conjugate, and H is a subgroup of G, which is invariant under conjugation by members of G (see here).
so here is what I have so far:
Let G be a finite group with H a normal subgroup of G such that |G|=p^k for some prime p. By Sylow's second theroem, H is contained in some Sylow p-subgroup of G. Sylow's third thereom says that any two Sylow p-subgroups of G are conjugate.
I am not sure after this, is that any two Sylow 0-subgroups being conjugate enough to show that H is contanied in ever p_Sylow subgroup of G since we know it is contained in one of the p-Sylow subgroups of G?
Sorry i am kind of slow on some of this stuff, i really appreciate the help.
If H is a normal subgroup of G than aH=Ha for all a in G. so aH(a^-1)=H, which means that if H conjugate is contained in Q, than H is contained in Q, right? So than we can apply this to every p-Sylow subgroup of G to show that a normal subgroup H of G is contained in every p-Sylow subgroup of G?