In a rational polynomial, complex roots always come in pairs of conjugates (because of the formula ).

So, as 2i is a root its complex conjugate is also a root. What is the complex conjugate of 2i?

Now, there is a rational polynomial of the form with these two complex numbers as roots. What is it?* This will then give you your answer...

*A hint for this bit would be that if p and q are roots of a quadratic polynomial P then P=(x-p)(x-q). Then expand.