Hi could someone pls help me with this...
If I have a line:
3x-2=4y-5=-z+2
and a normal:
r(5,-4,1)
how would I calculate the angle between them?
If you could show me how... I will do the rest
many thanks
I should think it would suffice to find any vector $\displaystyle \bf{a}$ in the direction of your line and calculate
$\displaystyle
\cos\theta = \frac{\bf{a}\cdot\bf{r}}{|\bf{a}||\bf{r}|}
$
To find such an $\displaystyle \bf{a}$, just find two points on your line and find the vector pointing between them.
What do you think? I'm not 100% sure so be critical!