Let A and B be similar matrices. Prove that there is a nice relationship between the eigenvectors of A and the eigenvectors of B

- April 28th 2010, 04:40 PMnicolem1051What is the relationship of the eigenvectors between 2 similar matrices?
Let A and B be similar matrices. Prove that there is a nice relationship between the eigenvectors of A and the eigenvectors of B

- April 28th 2010, 04:54 PMdwsmith
- April 28th 2010, 06:37 PMnicolem1051
vectors - yea that's what I can't figure out!

- April 28th 2010, 07:04 PMlovek323
I suppose you could say that the relationship between the eigenvectors is that they share the same eigenvalue. If you're looking for how to prove that the eigenvalues are the same, I have written a short proof here:

det(A-xI)=det(inv(P)BP-xI)

=det(inv(P)BP-inv(P)xIP)

=det(inv(P)(B-xI)P)

=det(B-xI)

Thus, as the characteristic polynomials are the same, the eigenvalues are the same.

I've put a formatted version up: Maths homework help - April 29th 2010, 04:50 AMHallsofIvy
If A and B are similar matrices, then there exist an invertible matrix P such that .

Let v be an eigenvector of A corresponding to eigenvalue . Then . Multiplying on both sides by P, so .

That is, if v is an eigenvalue of A corresponding to eigenvalue then Pv is an eigenvalue of B also corresponding to eigenvalue .

Of course, we can think of P as a "change of basis" matrix. That is, A and B represent the same linear transformation, written in different bases. The eigenvectors of A and B are representations of the same vector, written in different bases.