Originally Posted by

**thekrown** Okay if you don't mind I will say what I understood in my own words.

First I find the eigen values, subtract it from the diagonal. This gave us our matrix

1 0 0

0 1 0

1 1 0

from this point I can manupulate this matrix to obtain a reduced echelon form matrix.

Once I have my leading 1's, I can then find the value for x1, x2, x3.

In our case, it was simple once the reduction was made and we have the matrix

1 0 0

0 1 0

0 0 0

the third row can be removed, leaving us with a free variable for x3 and x1=0, x2=0.