For each divisor m of 6, give an example of a polynomial p(x) in Q[x], such that the splitting field E of p(x) over Q has m, ie [E:Q]=m

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- April 27th 2010, 07:03 AMapple2009polynomial
For each divisor m of 6, give an example of a polynomial p(x) in Q[x], such that the splitting field E of p(x) over Q has m, ie [E:Q]=m

- April 27th 2010, 08:09 PMFancyMouse
for m=3 you have to use some cubic polynomial whose determinant is a square in Q, so that the Galois group does not contain any odd permutations

for other cases, cyclotomic polynomial suffices - April 27th 2010, 09:44 PMaliceinwonderland
Seems like a slight typo there. It should be a "discriminant".

For a concrete example,

If , then the permutation is an element of if and only if it fixes the square root of the discriminant D.

We know that A_3 = Z_3. So the possible polynomial can be

and its discriminant is 49. Then, if the splitting field of f(x) is K, [K:Q]=3 and the order of Gal(K/Q) is 3. - April 29th 2010, 02:56 PMFancyMouse
>"discriminant".

Ah yes, thanks for pointing out.