Already found the solution ... only needed to realize that e.g. is a scalar then I can move it around and solve the proof.
Hello,
and are two column p-vectors
is a square matrix.
Trying to proof something (see attachment) ... I had to force it a bit and even though it feels right, I do not know exactly how to apply commutative law on the following products so that they can cancel out with the division I might be wrong but I think they both produce the same square matrix though looking at the original problem looks more like a scalar.
Basically I need to arrive to or .
I was trying something along the lines of but I can't arrive to the desired result.
Maybe I am applying the commutative rules wrongly ... btw I don't remember the rules name for this otherwise I would just look it up ..
If they did cancel the output would be 1 or Identity_p?
TIA,
Best regards,
bravegag
This is the proof I am trying to make: