Please look here
http://en.wikipedia.org/wiki/Magic_square.
For 3x3 min magic constant is 15.
If you add const to each cell then magic number will be 15+3*const.
It is proved here
Magic constant - Wikipedia, the free encyclopedia.
I have 8 equations, therefore 8 rows, but I do not know what a general matrix would look like for a 3x3 magic square. What I have so far is a matrix with letters as entries. Then I set the sum of each row, column, and diagonal equal to x.
I was told by others that the matrix is 8x11. I am pretty sure I have to augment the zero vector to the matrix and use Gauss-Jordan elimination. Can you please give me any suggestions?
Please look here
http://en.wikipedia.org/wiki/Magic_square.
For 3x3 min magic constant is 15.
If you add const to each cell then magic number will be 15+3*const.
It is proved here
Magic constant - Wikipedia, the free encyclopedia.
As I understood in magic square are numbers from 1 to n^2 if n=3 we get 1, 2, 3 ... to 9,
and matrix 3x3. Or I am not right?
I think in your matrix there must be 3 one's in a row, with 9 elements in a row.