the vectors {a1, a2, a3} are orthonormal
the vector a4 is a combination x1a1 + x2a2 + x3a3
after applying gram schmidt to the set of vectors {a1, a2, a3, a4} the resulting set of vectors will be:
{a1, a2, a3, zero vector}
is this correct?
the vectors {a1, a2, a3} are orthonormal
the vector a4 is a combination x1a1 + x2a2 + x3a3
after applying gram schmidt to the set of vectors {a1, a2, a3, a4} the resulting set of vectors will be:
{a1, a2, a3, zero vector}
is this correct?
Yes, if you do it in that order- that is, normalize to unit length, then "Gram-Schmidt" , etc. Since the first three are already orthonormal, you would just get , , again. And since is a linear combination of them, it has no "part" that is perpendicular to the space spanned by them- Gram-Schmidt would give the 0 vector.
But if you started by normalizing , then projecting, say, onto that to find a vector perpendicular to you would get 3 completely different vectors.