the vectors {a1, a2, a3} are orthonormal

the vector a4 is a combination x1a1 + x2a2 + x3a3

after applying gram schmidt to the set of vectors {a1, a2, a3, a4} the resulting set of vectors will be:

{a1, a2, a3, zero vector}

is this correct?

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- April 18th 2010, 03:42 AMNoxide[SOLVED] Gram-Schmidt
the vectors {a1, a2, a3} are orthonormal

the vector a4 is a combination x1a1 + x2a2 + x3a3

after applying gram schmidt to the set of vectors {a1, a2, a3, a4} the resulting set of vectors will be:

{a1, a2, a3, zero vector}

is this correct? - April 18th 2010, 06:41 AMHallsofIvy
Yes,

**if**you do it in that order- that is, normalize to unit length, then "Gram-Schmidt" , etc. Since the first three are already orthonormal, you would just get , , again. And since is a linear combination of them, it has no "part" that is perpendicular to the space spanned by them- Gram-Schmidt would give the 0 vector.

But if you started by normalizing , then projecting, say, onto that to find a vector perpendicular to you would get 3 completely different vectors.