if A is a singular matrix, must 0 be an eigenvalue of A?
my logic relied on the fact that the determinant of a singular matrix = 0... is this correct?
Yes to your question, though your logic works if you know that the determinant of a square matrix is the free coefficient if the matrix's characteristic polynomial...
Yes to your question, though your logic works if you know that the determinant of a square matrix is the free coefficient if the matrix's characteristic polynomial...
Tonio
Or if you know that the determinant of any matrix is just the product of all of its eigenvalues.