This question is part of a larger question, but I don't understand the solution I have been given here.
Show that there is no element of order 171 in the symmetric group .
Solution: The smallest n such that contains an element of order is n = 9 + 19 = 28.
I don't understand at all why that statement is true. The question comes at the end of a section about the Sylow theorems. Any help with this would be appreciated