prove: if (E:F)=P with p is a prime, then E=F(a) for each a is an element of E-F.
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Originally Posted by apple2009 prove: if (E:F)=P with p is a prime, then E=F(a) for each a is an element of E-F. [F(a):F] should divide [E:F]. Then it easily follows that E=F(a).
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