# Math Help - Find the absolute value

1. ## Find the absolute value

Find the absolute value and the argument $\theta$ in the range $0 <= \theta < 2\pi$ for $(1 - i\sqrt{3})^9$

I dun remember how to do this type of question, I wonder if someone can show me the process

2. Originally Posted by wopashui
Find the absolute value and the argument $\theta$ in the range $0 <= \theta < 2\pi$ for $(1 - i\sqrt{3})^9$

I dun remember how to do this type of question, I wonder if someone can show me the process
Use polar coordinates.

3. $1-i\sqrt{3}=2e^{-\frac{\pi i}{3}}$

4. And then $(1- i\sqrt{3})^9= 2^9 e^{9\left(\frac{\pi i}{3}\right)}= 2^9 e^{3\pi i}$