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Math Help - Find the absolute value

  1. #1
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    Find the absolute value

    Find the absolute value and the argument \theta in the range 0 <= \theta < 2\pi for (1 - i\sqrt{3})^9


    I dun remember how to do this type of question, I wonder if someone can show me the process
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  2. #2
    MHF Contributor Drexel28's Avatar
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    Quote Originally Posted by wopashui View Post
    Find the absolute value and the argument \theta in the range 0 <= \theta < 2\pi for (1 - i\sqrt{3})^9


    I dun remember how to do this type of question, I wonder if someone can show me the process
    Use polar coordinates.
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  3. #3
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    1-i\sqrt{3}=2e^{-\frac{\pi i}{3}}
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  4. #4
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    And then (1- i\sqrt{3})^9= 2^9 e^{9\left(\frac{\pi i}{3}\right)}= 2^9 e^{3\pi i}
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