Let A = $\displaystyle \begin{bmatrix}3&-\frac{1}{2}\\-6&5 \end{bmatrix}$

Find an invertible $\displaystyle S$ and a diagonal $\displaystyle D$ such that $\displaystyle S^{-1}AS = D$

S = $\displaystyle \begin{bmatrix}.&. \\.&. \end{bmatrix} $

D = $\displaystyle \begin{bmatrix}.&.\\.&. \end{bmatrix} $

I have never seen a problem like this and i am just a little confused on where to begin..

Thank you for any help :)