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**Iceflash234** Prove that $\displaystyle ord(a) = ord(bab^{-1})$

Here's what I have so far:

Part 1: Show that $\displaystyle ord(bab^{-1}) = n$

Suppose that ord (a) = n,

Then $\displaystyle a^n = e$

The problem I'm having is using the Associative Law to show that $\displaystyle (bab^{-1})^n$ is also e.

Part 2: Show that ord (a) = n.

Suppose that $\displaystyle ord(bab^{-1}) = n$

Then $\displaystyle (bab^{-1})^n = e$

The problem I'm having at this part is using the Associative Law to show that $\displaystyle a^n = e$.

Help is appreciated.