Originally Posted by emydawn
Now we may factor as follows:
(can you see why?)
This gives a pair of simultaneous equations in and , which I will leave for you to solve.
we have just learnt this topic but i dont understand how i would do this:
2x^4 + 3x^3 – 2x^2 + 4x – 6
x^2 + x – 2
using the remainder theorem
(aka in the form (Ax^2 + Bx + C)(x^2 + x – 2) + Dx + E
please help asap I have no idea how to do it, because there is a Dx and E at the end, and the power of 4 in the equn!