Let be a ring in which . Show that and that is commutative. Using closure under addition I can show that . However, I'm not too sure about this. Do I use the fact that so that ? I can't think of a way to show that .
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Originally Posted by nmatthies1 Let be a ring in which . Show that and that is commutative. Using closure under addition I can show that . However, I'm not too sure about this. Do I use the fact that so that ? I can't think of a way to show that . If you already reached the equality then of course that you can deduce since is true in any abelian group and thus in rings, too. Now, use this with to show that Tonio
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