Everything looks OK.Originally Posted by old & new
Correct. How did you solve 2x-5=17? You probably first added 5 to both sides, then you divided both sides by 2, since this is the factor multiplying x.Translate in an equation and solve:
five more than the quotient of a number and three is eight..
I need help with this one. I came up with x/3 + 5 = 8
Well, here you first subtract 5, then you multiply by the number dividing x.
Expand all the products. So 6(x-2) becomes 6x-12, therefore -6(x-2) becomes -6x+12, and 3(x-4) becomes 3x-12.Before I go, here is another...
solve: 2x - 6(x-2) = 3(x-4)
Then collect all terms that have an x in them on one side of the equality and all the terms without on the other. This can be done by adding and/or subtracting such terms to/from both sides of the equation.
Finally divide by the factor that multiplies x to obtain the solution.
Post your attempt here, and I'll let you know if it's right.