Linearly independent coordinate vectors help please?

I'm having trouble with proofs in linear algebra. I don't know where to start and how to go about the proofs.Any help would be appreciated.

(1) Let S be a basis for an n-dimensional vector space. Show that a set of vectors {v1,v2,...,vr} form a linearly independent set if and only if their coordinate vectors with respect to S namely (v1)s, (v2)s , ..., (vr)s are linearly independent in R^n.

I know that S being a basis for an n-dimensional vector space means that it is linearly independent and spans R^n but I don't know how to relate this to the proof.

(2)Show that if {v1,v2,...vr} span V, then (v1)s ,(v2)s ,..., (vr)s span R^n and conversely.

(This is a follow up from the previous question) I don't know where to start.

Any input would help. Thanks in advance

Re: Linearly independent coordinate vectors help please?

Added: The "standard basis" in $\displaystyle R^n$ is the set of vectors, <1, 0, 0, ..., 0>, <0, 1, 0, ..., 0> ..., <0, 0, 0,..., 1>. So write whatever vectors you are given in that form:

if $\displaystyle v_1= <v_{11}, v_{12}, ..., v_{1n}>$, $\displaystyle v_2= <v_{21}, v_{22}, ..., v_{2n}>$, ..., $\displaystyle v_n= <v_{n1}, v_{n2}, ..., v_{nn}>$.

Then $\displaystyle a_1v_1+ a_2v_2+ ....+ a_nv_n= <a_1v_{11}+ a_2v_{21}+...+ a_nv_{n1}, a_1v_{12}+ a_2v_22+ ....+ a_nv{n2}, ..., a_1v_{1n}+ a_2v_{2n}+ ...+ a_nv_{nn}>$.