I hava a orthogonal basis {1, t, $\displaystyle 3t^2-1$ , $\displaystyle 5t^3-3t$}

and this normalized is

{1,t, $\displaystyle 1/2(3t^2-1)$, $\displaystyle 1/2(5t^3-3t)$}

I dont understand how they have done this. Any help would be much appreciated. Thanks.