I feel like this is a really stupid question but I just can't figure out how to solve it:

If ||u|| = 2 and ||v|| = http://upload.wikimedia.org/math/2/2...0d2391a896.png and u (dot) v = 1, find ||u (dot) v||

Thanks for the help!

Printable View

- February 20th 2010, 07:57 PMLaydieofsorrowsNorm of Vectors
I feel like this is a really stupid question but I just can't figure out how to solve it:

If ||**u**|| = 2 and ||**v**|| = http://upload.wikimedia.org/math/2/2...0d2391a896.png and u (dot) v = 1, find ||u (dot) v||

Thanks for the help!

- February 21st 2010, 02:56 AMtonio

It's not stupid but something's wrong here: both the dot product and the norm are defined for vectors (the first one for two, the second one for one) and give back a scalar (a number), so ||u (dot) v|| is the norm of a scalar, not a vector, and this doesn't make much sense. Read carefully the question again.

Tonio - February 21st 2010, 08:54 PMLaydieofsorrows
I checked the problem and it's correct.

Can I get another opinion? - February 21st 2010, 11:56 PMtonio
- February 22nd 2010, 12:22 AMOpalg
You can trust tonio, he's an expert. Seriously, if the question is as stated then either it's a trick question or there's a mistake in it. If the norm of a scalar means anything at all, then it must just mean the absolute value. So if u (dot) v = 1, then ||u (dot) v|| = 1.

- February 22nd 2010, 02:11 AMHallsofIvy
Is it possible that the problem asked for , the norm of the

**cross product**of u and v?

If so, you could use the facts that and , where is the angle between u and v.

Since you are given that as well as the values of ||u|| and ||v||, you can solve for . Use that to find (which must be between 0 and ) and then find .