1. ## Find determinant

$det(2A^8 B^{-1})$

I tried to break it up but I'm not sure where the 2 goes.

$det(2A^8) det(B^{-1})$ ?

Any help is appreciated!

2. $
\det(2A^{8}B^{-1})=
2^{3}\det(A^{8})\det(B^{-1})=
8\frac{\det(A)^{8}}{\det(B)}=
8\frac{ (-1)^{8}}{-2} = -4
$