For the first question, the matrix B is just the adj(A)?

I have no idea where to begin with the second question, if anyone could help me get started.

Any help is greatly appreciated! (Rofl)

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- Feb 18th 2010, 01:11 PMDarKFind the determinant given the adjoint
For the first question, the matrix B is just the adj(A)?

I have no idea where to begin with the second question, if anyone could help me get started.

Any help is greatly appreciated! (Rofl) - Feb 18th 2010, 02:41 PMo_O
The easiest way to do it..

Given that A is an invertible, nxn matrix, we have that: $\displaystyle \det (A) = \sqrt[n-1]{\det \big[ \text{adj} (A) \big]}$

This can be derived from the relationship: $\displaystyle \det (A) A^{-1} = \text{adj} (A)$

where you take the determinant of both sides and solve.