Thread: Permutations and Abelian Group proof.

Originally Posted by Amer

Ah, I get it now! Thanks very much!

So now, with Alpha*Eta = Beta,

that means Eta = Alpha^(-1) * Beta, how do you go about computing that?

After some calculations, would I be correct to state that:

Alpha^(-1) = Alpha

That's what I found. There what I need to compute is:

Eta = AlphaBeta

Originally Posted by MickQ

After some calculations, would I be correct to state that:

Alpha^(-1) = Alpha

That's what I found. There what I need to compute is:

Eta = AlphaBeta

ok it is easy now to solve it



simplify it