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Originally Posted by Amer Ah, I get it now! Thanks very much! So now, with Alpha*Eta = Beta, that means Eta = Alpha^(-1) * Beta, how do you go about computing that?
After some calculations, would I be correct to state that: Alpha^(-1) = Alpha That's what I found. There what I need to compute is: Eta = AlphaBeta
Originally Posted by MickQ After some calculations, would I be correct to state that: Alpha^(-1) = Alpha That's what I found. There what I need to compute is: Eta = AlphaBeta ok it is easy now to solve it simplify it
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