14. Solve the systems in all parts simultaneously.
A = B
1 3 5 = b1
-1 -2 0 = b2
2 5 4 = b3
a) b1=1, b2=0, b3=-1
b) b1=0, b2=1, b3=1
c) b1=-1, b2=-1, b3=0
So the way my prof instructed us to solve this is to setup up the matrix with the a,b,c B columns on the right and reduce the matrix to identity format:
1**: a)b1 : a)b2 : a)b3
01*: b)b1 : b)b2 : b)b3
001: c)b1 : c)b2 : c)b3
I set it up like this
1 3 5 : 1:0 :-1
-1 -2 0 : 0:1 :-1
2 5 4 :-1:1: 0
I reduced the matrix to the identity matrix and here is my result
1 3 5 : 1 : 0 :-1
0 1 5 : 1 : 1 :-2
0 0 1 : 2 :-2 : 4
I think I got it all good except I'm not sure if there is more to do. Did I answer the question correctly?