14. Solve the systems in all parts simultaneously.

A = B

1 3 5 = b1

-1 -2 0 = b2

2 5 4 = b3

a) b1=1, b2=0, b3=-1

b) b1=0, b2=1, b3=1

c) b1=-1, b2=-1, b3=0

So the way my prof instructed us to solve this is to setup up the matrix with the a,b,c B columns on the right and reduce the matrix to identity format:

1**: a)b1 : a)b2 : a)b3

01*: b)b1 : b)b2 : b)b3

001: c)b1 : c)b2 : c)b3

I set it up like this

1 3 5 : 1:0 :-1

-1 -2 0 : 0:1 :-1

2 5 4 :-1:1: 0

I reduced the matrix to the identity matrix and here is my result

1 3 5 : 1 : 0 :-1

0 1 5 : 1 : 1 :-2

0 0 1 : 2 :-2 : 4

I think I got it all good except I'm not sure if there is more to do. Did I answer the question correctly?