# Thread: commutativity of a group

1. ## commutativity of a group

I'm trying to prove this problem but I'm not sure whether or not my answer is working. The problem states

"Let G be a group, with the following property: Whenever a, b, and c belong to G and ab=ca, then b=c. Prove that G is abelian."

I have solved for b and c using inverses, and got that b=a-1(ca) and c=(ab)a-1. The second half of the problem states that b=c. So I wanted to use replacement to show that the group is abelian. But I'm not sure if that would prove G is abelian for any arbitrary b and c or if its only commutative for this exact pair.

2. Hi

Perhaps it is better to start with two elements, let's say $a,b,$ in $G.$ You want to prove $ab=ba$.

Inverses are indeed often useful for group equations: take a look at $ab=ab(a^{-1}a)$ using associativity and your hypothesis.

3. I'm sorry I don't think I understand. I could regroup by the associative property stating
ab=(aba-1)a
and I previously found that c=(aba-1) so by replacement ab=ca so therefore b=c. But I'm still confused about how to prove the group is abelian. I'm missing something.

4. Well, you have $ab=(aba^{-1})a$

You can define $c:=aba^{-1}$ if you want, so, by hypothesis, you have: $b=c,$ i.e. $b=aba^{-1},$ and you can conclude.

5. yea i realized that a couple minutes after i had replied. thank you sooo much for the explanation!