It's an easy question...

Let and

Show that is in Span{u,v} for all a and b. In other words = Span{u,v}

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- Jan 25th 2010, 06:27 PMTanderProve span
It's an easy question...

Let and

Show that is in Span{u,v} for all a and b. In other words = Span{u,v} - May 22nd 2010, 10:02 PMdwsmith
- May 23rd 2010, 04:53 AMHallsofIvy
Directly from the definition: solve

for x and y. If you**can**then .

That is the same as solving x+ y= a, 2x- 2y= b. Multiply the first equation by 2 and add: 4x= 2a+ b so x= (2a+ b)/4. Multiply the first equation by 2 and subtract: 4y= 2a- b so y= (2a- b)/4. Those exist for all a and b.